address match list syntaxs

[Mark_Andrews at isc.org]

> You mean A.B.C.D/E + A.B.C+1.D/E = A.B.C.D/E-1 right?
> Assuming C is even.
> If thats not what you mean then I don't  understand.
> 
> george

	A.B.C.D/E + A.B.C.D+1/E = A.B.C.D/E-1 	D even
	A.B.C.0/E + A.B.C+1.0/E = A.B.C.0/E-1	C even
	A.B.0.0/E + A.B+1.0.0/E = A.B.0.0/E-1	B even
	A.0.0.0/E + A+1.0.0.0/E = A.0.0.0/E-1	A even

	Mark
--
Mark Andrews, Internet Software Consortium
1 Seymour St., Dundas Valley, NSW 2117, Australia
PHONE: +61 2 9871 4742                 INTERNET: Mark.Andrews at isc.org